118=12x^2+9x

Solution for 118=12x^2+9x equation:

118=12x^2+9x

We move all terms to the left:

118-(12x^2+9x)=0

We get rid of parentheses

-12x^2-9x+118=0

a = -12; b = -9; c = +118;
Δ = b2-4ac
Δ = -92-4·(-12)·118
Δ = 5745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{5745}}{2*-12}=\frac{9-\sqrt{5745}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{5745}}{2*-12}=\frac{9+\sqrt{5745}}{-24}
$